|
circumferential speed |
load factor |
|
5 |
0.95 |
|
10 |
0.75 |
|
20 |
0.45 |
|
30 |
0.37 |
|
40 |
0.12 |
|
50 |
0.08 |
Example
Speedy 10/50 with non-preloaded POM-C nut, d0 = 10 mm, p = 50 mm
and C0 = 1250 N;
required moving speed vS = 200 mm/sec.
We need to find: Fper.
We calculate n [min-1],
circumferential speed vC [m/min]
fL at vC of 7.53 m/min ≈ 0.85 [-]
It follows: Fper. = C0 · fL = 1250 · 0.85 = 1062.5 N
In other words, the maximum load for a Speedy 10/50 at vS = 200 mm/sec. (
n = 240 min-1) is 1060 N.